Silver

[thomasgrant]

Hi Silver.
Got a few questions for you regarding stack_array and combo bets.

procedure stack_array(sa_elements; var sa_elements);

~~~~~~~~~~~~~~~~~~~~

In stack_array.
You have this.

Code:

print('Spin count - '+IntToStr(spin_count)+'. We have bet '+currency+FormatFloat('0.##',unit_value*sa_elements[k,9,k1]*sa_elements[k,5,sa_elements[k,2,k1]])+' on '+sa_elements[k,4,k1]+' and win.');

or this.

Code:

print('Spin count - '+IntToStr(spin_count)+'. We have bet '+currency+FormatFloat('0.##',unit_value*sa_elements[k,9,k1]*sa_elements[k,5,sa_elements[k,2,k1]])+' on '+sa_elements[k,4,k1]+' and lose.');

But when you do a simple 'Neighbors_1' bet
It will say that it placed $1 on 'Neighbors_1' instead of saying that it placed $5 on 'Neighbors_1'
Because 'Neighbors_1' has 5 chips on it.

Can you show me how to fix this?

~~~~~~~~~~~~~~~~~~~~~

Combo of 3 ECs

Code:

[[0],[1],[0],1,
['Red_Odd_Low',
'Red_Even_Low',
'Red_Odd_High',
'Red_Even_High',
'Black_Odd_Low',
'Black_Even_Low',
'Black_Odd_High',
'Black_Even_High'],
[0,1,2,4,8,16,32,64,128,256,512,1024,2048],
3,{6}
[0],0,[1],                                    
'EC_Combo3'],

Similar question for a combo bet like this.
If only one out of the 3 win.
So for instance.
It lands on Red.
But not Low or odd.
I seem to get a balance error.
The balance goes out.
I am trying to trace it down.

You got any clues?

[thomasgrant]

Also can you check this?

This is for BV Zero table.
If zero turns up while no betting.

Code:

if was_betting=0 then
begin
bet_x_on_y(chips[1],['Red','Black'],chips);
if number_is(last_nr,'Single_0')then amount:=amount-(unit_value*elements[k,9,k1]*elements[k,5,elements[k,2,k1]]*elements[k,6]);
end;

[Silver]

Well let's answer each question.
1.

But when you do a simple 'Neighbors_1' bet
It will say that it placed $1 on 'Neighbors_1' instead of saying that it placed $5 on 'Neighbors_1'
Because 'Neighbors_1' has 5 chips on it.
Can you show me how to fix this?

It is simple - you should just add the count_of elements that form the current group
print('Spin count - '+IntToStr(spin_count)+'. We have bet '+currency+FormatFloat('0.##',unit_value*sa_elements[k,9,k1]*sa_elements[k,6]*sa_elements[k,5,sa_elements[k,2,k1]])+' on '+sa_elements[k,4,k1]+' and win.');

2.

Combo of 3 ECs

Well as I know it must work with any possible groups.
Check please that your created groups (in utils) - are created correct. I mean the number_is function - there you should check the numbers for any combo to be setted correct.

3.

This is for BV Zero table.
If zero turns up while no betting.

if was_betting=0 then
      begin
         bet_x_on_y(chips[1],['Red','Black'],chips);
         if number_is(last_nr,'Single_0')then amount:=amount-(unit_value*elements[k,9,k1]*elements[k,5,elements[k,2,k1]]*elements[k,6]);
      end;

It will not work.
You check the landed number to be 0 - without making a spin.

[thomasgrant]

Ok, that helped a little.
Now take a look at this.

Here is the element section.

Code:

[[0],[1],[0],1,
['Red_Odd_Low',
'Red_Even_Low',
'Red_Odd_High',
'Red_Even_High',
'Black_Odd_Low',
'Black_Even_Low',
'Black_Odd_High',
'Black_Even_High'],
[0,1,2,4,8,16,32,64,128,256,512,1024,2048],
3,{6}
[-1],0,[1],                                   
'EC_Combo3'],

Here is the bet_on_x section.

Code:

{Even Chances Combos x3}
'Red_Odd_Low':begin
click_red();click_odd();click_low();
end;
'Red_Even_Low':begin
click_red();click_even();click_low();
end;
'Red_Odd_High':begin
click_red();click_odd();click_high();
end;
'Red_Even_High':begin
click_red();click_even();click_high();
end;

'Black_Odd_Low':begin
click_black();click_odd();click_low();
end;
'Black_Even_Low':begin
click_black();click_even();click_low();
end;
'Black_Odd_High':begin
click_black();click_odd();click_high();
end;
'Black_Even_High':begin
click_black();click_even();click_high();
end;

Here is the in array section.

Code:

{Even Chances Combos x3}
'Red_Odd_Low':if in_array(number,
[1,3,5,7,9,12,14,16,18,19,21,23,25,27,30,32,34,36,
1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18]) then result:=True;
'Red_Even_Low':if in_array(number,
[1,3,5,7,9,12,14,16,18,19,21,23,25,27,30,32,34,36,
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18]) then result:=True;
'Red_Odd_High':if in_array(number,
[1,3,5,7,9,12,14,16,18,19,21,23,25,27,30,32,34,36,
1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,
19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36]) then result:=True;
'Red_Even_High':if in_array(number,
[1,3,5,7,9,12,14,16,18,19,21,23,25,27,30,32,34,36,
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,
19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36]) then result:=True;

'Black_Odd_Low':if in_array(number,
[2,4,6,8,10,11,13,15,17,20,22,24,26,28,29,31,33,35,
1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18]) then result:=True;
'Black_Even_Low':if in_array(number,
[2,4,6,8,10,11,13,15,17,20,22,24,26,28,29,31,33,35,
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18]) then result:=True;
'Black_Odd_High':if in_array(number,
[2,4,6,8,10,11,13,15,17,20,22,24,26,28,29,31,33,35,
1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,
19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36]) then result:=True;
'Black_Even_High':if in_array(number,
[2,4,6,8,10,11,13,15,17,20,22,24,26,28,29,31,33,35,
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,
19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36]) then result:=True;

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
I think the problem lies here.

Code:

amount:=amount+(unit_value*sa_elements[k,9,k1]*sa_elements[k,5,sa_elements[k,2,k1]]*(sa_elements[k,3]-(sa_elements[k,6]-1)));//in case the red win we increase the amount

Now here is a video of it in action.
http://rouletteprofesor.com/vids/b1a/b1a.mp4

[thomasgrant]

Hmmm seems to be ok with just about everything else except these EC bets.
More testing to go.

[Silver]

Well Thomas I have looked one more time to your setting - and need to say that it will not work.
I have to say also - IT MUST NOT WORK - at least in current scripts.
I will explain why.

please look in some script and find the next row:

Code:

6 cnt_elements - indicate how much same table-elements we have in the group, usuall =1 (for example we have [0,10,0,??,'groupA'[0,1,1,1,2,2,3,4,5,7,9,12]
  where groupA - is the 9 singles. In this case the win_coeficient must remain 35, and the cnt_elements=9.
  So the correct will be [0,10,0,35,'groupA',[0,1,1,1,2,2,3,4,5,7,9,12],9])

So it tell - indicate how much same table-elements
Same table elements - mean that in case you have for example 4 elements in the group - then the singles that form each element must not be same as singles from other 3 elements.
An example of good group is:
            'split1_4': click_split_bet_1_4();
            'split2_3': click_split_bet_2_3();
            'split5_6': click_split_bet_5_6();
            'split7_8': click_split_bet_7_8();

The script calculate the next things:
in case we have a group with 4 elements - and in case of win - it mean that win only one element from the group - and the rest 3 elements lost.

An example of bad group is
            'split1_4': click_split_bet_1_4();
            'split2_3': click_split_bet_2_3();
            'split2_5': click_split_bet_2_5();
            'split5_6': click_split_bet_5_6();
Here in case landed number is 2 (or 5) - we will have 2 wining elements - but the script will treat this as 1-win and 3-lost.

So these combinations are exceptions - and in order to treat them - there need to be some individual code - something like for voisins.
I have to regret you - but these combinations don't meet the rules of universality.

[thomasgrant]

But it's only a combo of Even chances bets.
Bet on Red, Even, Low. All 3.
Why is that so hard?
Everything else seems ok.
Even a combo of 2 Even Chances.
Red and Low.
Why should that cause problems?

[Silver]

Thomas - even a combo of 2 Even Chances - Red and Low - will not work correct.
Let say that landed number is 1 - so it is Red and at the same time it is Low.
So you will obtain double profit, but the script will consider that one won and the other lost.

Of course it is possible to manage these combos correct - but in order to do this - there is need some serious modifications to the script.

[thomasgrant]

Thomas - even a combo of 2 Even Chances - Red and Low - will not work correct.
Let say that landed number is 1 - so it is Red and at the same time it is Low.
So you will obtain double profit, but the script will consider that one won and the other lost.

Of course it is possible to manage these combos correct - but in order to do this - there is need some serious modifications to the script.

Ohh...
Ok...
Most of the other combos seem fine.
What about Dozens and columns then?
If I am playing 2 dozens.
And or two columns.

Combo splits, corners all seem ok.

As for the combo Even Chances.
Hmmm...
If you don't wana show me.
Or if you don't have time to tell me.
Then ok.

[Silver]

Well - just take a look at your combos.
What combos - are composed by elements that cover the same singles?
I have saw - at your utils - and found that such combos - are only EC combos.

And there is combination Red with Odd- why such combination?
And I am curios - are these EC combos efficient? Is there some reason to use Red and Odd - as one element?

In this case why you don't use line1 and line2 (for example) - as one element?

[thomasgrant]

Well - just take a look at your combos.
What combos - are composed by elements that cover the same singles?
I have saw - at your utils - and found that such combos - are only EC combos.

And there is combination Red with Odd- why such combination?
And I am curios - are these EC combos efficient? Is there some reason to use Red and Odd - as one element?

In this case why you don't use line1 and line2 (for example) - as one element?

Well Silver.
In other software that I have.
I can play EC combos.
Hmmmm....
You know....
I may not need to play them as combos.
As for Line combos.
I have them already.
I think I got this figured out now.

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